{"id":17884,"date":"2024-03-08T04:08:58","date_gmt":"2024-03-08T04:08:58","guid":{"rendered":"https:\/\/soicau5024.minhngocxoso.com\/?p=17884"},"modified":"2024-03-08T04:08:58","modified_gmt":"2024-03-08T04:08:58","slug":"tuyet-chieu-du-doan-xo-so-mien-nam-chinh-xac","status":"publish","type":"post","link":"https:\/\/soicauxs168.com\/tuyet-chieu-du-doan-xo-so-mien-nam-chinh-xac\/","title":{"rendered":"tuy\u1ec7t chi\u00eau d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n nam ch\u00ednh x\u00e1c"},"content":{"rendered":"
<\/p>\n\n\n
L\u00e0m sao c\u00f3 th\u1ec3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n Nam ch\u00ednh x\u00e1c? Ch\u1eafc h\u1eb3n \u0111\u00e2y l\u00e0 c\u00e2u h\u1ecfi \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u ng\u01b0\u1eddi quan t\u00e2m. \u0110\u1ed1i v\u1edbi nh\u1eefng ng\u01b0\u1eddi hay c\u00e1 c\u01b0\u1ee3c th\u00ec c\u00f3 r\u1ea5t nhi\u1ec1u b\u00ed quy\u1ebft hay ho \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n cho m\u00ecnh m\u1ed9t con x\u1ec9u ch\u1ee7 mi\u1ec1n nam hay con l\u00f4 3 s\u1ed1 mi\u1ec1n nam,\u2026 . Nh\u01b0ng nh\u01b0 v\u1eady \u0111\u00e3 l\u00e0 \u0111\u1ee7 ch\u01b0a? C\u00f9ng t\u00ecm hi\u1ec3u th\u00eam nhi\u1ec1u b\u00ed quy\u1ebft h\u01a1n nh\u00e9.<\/p>\n\n\n\n
Kinh nghi\u1ec7m ch\u01a1i k\u00e9p: s\u1ed1 k\u00e9p l\u00e0 s\u1ed1 c\u00f3 2 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gi\u1ed1ng nhau. S\u1ed1 n\u00e0y r\u1ea5t d\u1ec5 nh\u1eadn ra nh\u01b0ng \u0111\u1ec3 bi\u1ebft l\u00e0m sao \u0111\u1ec3 bi\u1ebft s\u1eafp xu\u1ea5t hi\u1ec7n k\u00e9p? Quan s\u00e1t th\u1ea5y t\u1eeb 2-3 ng\u00e0y li\u00ean t\u1ee5c \u0111\u1ec3 nh\u1eadn bi\u1ebft c\u00f3 s\u1ed1 k\u00e9p. T\u1eeb \u0111\u00f3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n Nam ch\u00ednh x\u00e1c nh\u1ea5t c\u00f3 th\u1ec3.<\/p>\n\n\n\n
Ch\u01a1i \u0111\u1ea7u 0 v\u00e0 \u0111u\u00f4i 0: D\u1ea5u hi\u1ec7u \u0111\u1ec3 xu\u1ea5t hi\u1ec7n \u0111\u1ea7u 0, \u0111u\u00f4i 0 b\u1ea1n \u0111\u00e3 bi\u1ebft ch\u01b0a? \u0110\u1ec3 nh\u1eadn bi\u1ebft, ng\u01b0\u1eddi ch\u01a1i c\u1ea7n ph\u1ea3i theo d\u00f5i v\u00e0 th\u1ed1ng k\u00ea c\u00e1c s\u1ed1 xu\u1ea5t hi\u1ec7n trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t. Khi \u1edf gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u00f3 xu\u1ea5t hi\u1ec7n s\u1ed1 0 n\u0103m gi\u1eefa ch\u00ednh (v\u00ed d\u1ee5 12034) th\u00ec d\u1ef1 \u0111o\u00e1n k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 h\u00f4m sau \u0111\u1ea7u 0 \u0111u\u00f4i 0 s\u1ebd xu\u1ea5t hi\u1ec7n r\u1ea5t cao.<\/p>\n\n\n\n
V\u00e0 m\u1ed9t c\u00e1ch n\u1eefa \u0111\u00f3 l\u00e0 theo d\u00f5i c\u00e1c con s\u1ed1 qua c\u00e1c con gi\u00e1p theo tu\u1ea7n.<\/p>\n\n\n\n
H\u00e3y \u00e1p d\u1ee5ng nh\u1eefng nguy\u00ean t\u1eafc tr\u00ean linh ho\u1ea1t. N\u1ebfu ki\u00ean tr\u00ec \u00e1p d\u1ee5ng, ch\u1eafc ch\u1eafn m\u1ed9t ng\u00e0y kh\u00f4ng xa b\u1ea1n s\u1ebd d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 ch\u00ednh x\u00e1c.<\/p>\n\n\n\n \u0110\u1ec3 d\u1ef1 \u0111o\u00e1n ch\u00ednh x\u00e1c th\u00ec vi\u1ec7c t\u00ednh s\u1ed1 v\u1ecb tr\u00ed kh\u00e1 l\u00e0 quan tr\u1ecdng. B\u1ea1n ph\u1ea3i n\u1eafm \u0111\u01b0\u1ee3c ch\u00ednh x\u00e1c nh\u1eefng \u0111i\u1ec1u c\u01a1 b\u1ea3n c\u1ee7a s\u1ed1 v\u1ecb tr\u00ed c\u1ea7u l\u00f4 th\u00ec m\u1edbi soi \u0111\u00fang. B\u1ea1n c\u00f3 th\u1ec3 quan s\u00e1t \u0111\u01a1n gi\u1ea3n trong c\u00e1ch t\u00ednh c\u1ee7a ch\u00fang t\u00f4i d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n\n\n\n C\u00e1c gi\u1ea3i \u0111\u1eb7c bi\u1ec7t I, II, III lu\u00f4n c\u00f3 5 s\u1ed1, t\u1eeb \u0111\u00f3 ta s\u1ebd c\u00f3 10 gi\u1ea3i x 5 = 50 s\u1ed1.<\/p>\n\n\n\n 4 gi\u1ea3i T\u01b0 v\u00e0 6 gi\u1ea3i N\u0103m m\u1ed7i gi\u1ea3i \u0111\u1ec1u c\u00f3 4 s\u1ed1, t\u1eeb \u0111\u00f3 ta c\u00f3 (4+6) x 4 = 40 s\u1ed1.<\/p>\n\n\n\n 3 gi\u1ea3i 6 m\u1ed7i gi\u1ea3i \u0111\u1ec1u c\u00f3 3 s\u1ed1, t\u1eeb \u0111\u00f3 ta s\u1ebd c\u00f3 3 \u00d7 3 = 9 s\u1ed1.<\/p>\n\n\n\n 4 gi\u1ea3i B\u1ea3y m\u1ed7i gi\u1ea3i \u0111\u1ec1u l\u00e0 2 s\u1ed1, t\u1eeb \u0111\u00f3 ta c\u00f3 4 \u00d7 2 = 8 s\u1ed1.<\/p>\n\n\n\n Sau \u0111\u00f3, theo nh\u01b0 c\u00e1c v\u1ecb tr\u00ed c\u1ee7a s\u1ed1 gi\u1ea3i s\u1ebd c\u00f3: 50 + 40 + 9 + 8 =107 s\u1ed1 hay 107 v\u1ecb tr\u00ed kh\u00e1c nhau.<\/p>\n\n\n\n B\u1ea1n c\u00f3 th\u1ec3 v\u1eadn d\u1ee5ng c\u00e1c v\u1ecb tr\u00ed n\u00e0y \u0111\u1ec3 s\u1eafp x\u1ebfp v\u00e0 th\u1ed1ng k\u00ea d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1. Nh\u1eefng c\u00e1ch d\u1ef1 \u0111o\u00e1n n\u00e0y v\u00f4 c\u00f9ng \u0111a d\u1ea1ng. Ch\u00fac b\u1ea1n th\u00e0nh c\u00f4ng!<\/p>\n\n\n <\/p>\r\nSoi c\u1ea7u d\u1ef1 \u0111o\u00e1n qua v\u1ecb tr\u00ed ch\u00ednh x\u00e1c<\/h2>\n\n\n\n
TH\u1ea6N T\u00c0I CH\u1ed0T S\u1ed0<\/span><\/strong><\/h4>\r\n